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JEE MAIN 2019
09-04-2019 - S1
Question
If the function f defined on $\left(\frac{\pi}{6}, \frac{\pi}{3}\right)$ by $f(x)=\left\{\begin{array}{cc}\frac{\sqrt{2} \cos x-1}{\cot x-1}, & x \neq \frac{\pi}{4} \\ k, & x=\frac{\pi}{4}\end{array}\right.$ is continuous, then k is equal to :
Select the correct option:
A
1
B
$\frac{1}{2}$
C
$\frac{1}{\sqrt{2}}$
D
2
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Mathematics
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