If the shortest distance between the straight lines... | 3D Geometry | JEE Main

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JEE MAIN_2021_

22-JULY-2021,S2

Question

If the shortest distance between the straight lines $3(x-1)=6(y-2)=2(z-1)$ and $4(x-2)=2(y-\lambda)=(z-3)$, $\lambda \in \mathrm{R}$ is $\frac{1}{\sqrt{38}}$, then the integral value of $\lambda$ is equal to:

Select the correct option:

A

3

B

2

C

5

D

-1

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

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