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JEE MAIN 2021
27-08-2021 S1
Question
If $U_n=\left(1+\frac{1}{n^2}\right)\left(1+\frac{2^2}{n^2}\right)^2 \cdots\left(1+\frac{n^2}{n^2}\right)^n$, then $\lim _{n \rightarrow \infty}\left(U_n\right)^{n^{\frac{-4}{2}}}$ is equal to :
Select the correct option:
A
$\frac{e^2}{16}$
B
$\frac{4}{e}$
C
$\frac{16}{e^2}$
D
$\frac{4}{e^2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Mathematics
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