In a double slit experiment |Wave Optics|JEE - MAIN - 2019

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JEE MAIN 2019

12.04.19_S1

Question

In a double slit experiment, when a thin film of thickness $t$ having refractive index $\mu$ is introduced in front of one of the slits, the maximum at the centre of the fringe pattern shifts by one fringe width. The value of $t$ is ( $\lambda$ is the wavelength of the light used):

Select the correct option:

A

$\frac{2 \lambda}{(\mu-1)}$

B

$\frac{\lambda}{3(\mu-1)}$

C

$\frac{\lambda}{(2 \mu-1)}$

D

$\frac{\lambda}{(\mu-1)}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & \mu t-t=\lambda \\ & t(\mu-1)=\lambda \quad \Rightarrow \quad t=\frac{\lambda}{(\mu-1)}\end{aligned}$

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