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JEE Advance 2015
Paper-2
Multiple correct answers - Select all that apply
Question
In a thin rectangular metallic strip a constant current I flows along the positive x-direction, as shown in the figure. The length, width and thicknes of the strip are $\mathrm{I}, \mathrm{w}$ and d , respectively.

A uniform magnetic field $\vec{B}$ is applied on the strip along the positive $y$-direction. Due to this, the charge carriers experience a net deflection along the $\mathbf{z}$-direction. This results in accumulation of charge carriers on the surface PQRS and is appearance of equal and opposite charges on the face opposite to PQRS. A potential difference along the z -direction is thus developed. Charge accumulation continues until the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross section of the strip and carried by electrons.

Consider two different metallic strips (1 and 2) fo the same material. Their lengths are the same, width are $w_1$ and $w_2$ and thicknesses are $d_1$ and $d_2$, respectively. Two points $K$ and $M$ are symmetrically located on the opposite faces parallel to the $x-y$ plane (see figure). $V_1$ and $V_2$ are the potential differences between $K$ and $M$ in strips 1 and 2, respectively. Then, for a given current I flowing through them in a given magnetic field strength B , the correct statement(s) is (are)
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Select ALL correct options:
A
If $\mathrm{w}_1=\mathrm{w}_2$ and $\mathrm{d}_1=2 \mathrm{~d}_2$, then $\mathrm{V}_2=2 \mathrm{~V}_1$
B
If $\mathrm{w}_1=\mathrm{w}_2$ and $\mathrm{d}_1=2 \mathrm{~d}_2$, then $\mathrm{V}_2=\mathrm{V}_1$
C
If $w_1=2 w_2$ and $d_1=d_2$, then $V_2=2 V_1$
D
If $w_1=2 w_2$ and $d_1=d_2$, then $V_2=V_1$
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