In a triangle X Y Z, let $x, y, z$ be the lengths of sides opposite to the angle $X, Y, Z$ respectively, and $2 s=x+y+z$, If $\frac{s-x}{4}=\frac{s-y}{3}=\frac{s-z}{2}$ and area of incircle of the triangle $X Y Z$ is $\frac{8 \pi}{3}$, then
Select ALL correct options:
A
area of the triangle XYZ in $6 \sqrt{6}$
B
the radius of circumcircle of the triangle $X Y Z$ is $\frac{35}{6} \sqrt{6}$
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