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JEE MAIN_2019
_S2_100419
Question
In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line. One may conclude that:
Question Image
Select the correct option:
A
$\mathrm{R}(\mathrm{T})=\frac{\mathrm{R}_0}{\mathrm{~T}^2}$
B
$R(T)=R_0 e^{-T_0^2 / T^2}$
C
$\mathrm{R}(\mathrm{T})=\mathrm{R}_0 \mathrm{e}^{-\mathrm{T}_0^2 / \mathrm{T}_0^2}$
D
$R(T)=R_0 e^{T^2 / T_0^2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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