In sulphur estimation, $2.0 \times 10^{-3} \mathrm{~mol}$ of an organic compound $(\mathrm{X})$ (molar mass $76 \mathrm{~g} \mathrm{~mol}^{-1}$ ) gave 0.4813 g of barium sulphate (molar mass $233 \mathrm{~g} \mathrm{~mol}^{-1}$ ). The percentage of sulphur in the compound $(\mathrm{X})$ is $\_\_\_\_$ $\times 10^{-1} \%$ (Nearest integer)