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JEE Advance 2006
Multiple Correct Type
Multiple correct answers - Select all that apply
Question
Internal bisector of $\angle \mathrm{A}$ of triangle ABC meets side BC at D . A line drawn through D perpendicular to AD intersects the side $A C$ at $E$ and the side $A B$ at $F$. If $a, b, c$ represent sides of $\triangle A B C$ then
Select ALL correct options:
A
AE is HM of b and c
B
$A D=\frac{2 b c}{b+c} \cos \frac{A}{2}$
C
$\mathrm{EF}=\frac{4 \mathrm{bc}}{\mathrm{b}+\mathrm{c}} \sin \frac{\mathrm{A}}{2}$
D
the triangle AEF is isosceles
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
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JEE Advance
Mathematics
Easy
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