Lim n→∞ {(2^½−2^⅓)(2^½−2^⅕)...}... | Limits

JEE MAIN 2023

08-04-2023 (S2)

Question

$\operatorname{Lim}_{n \rightarrow \infty}\left\{\left(2^{\frac{1}{2}}-2^{\frac{1}{3}}\right)\left(2^{\frac{1}{2}}-2^{\frac{1}{5}}\right) \cdots \cdots\left(2^{\frac{1}{2}}-2^{\frac{1}{2 n+1}}\right)\right\}$ is equal to

Select the correct option:

$\frac{1}{\sqrt{2}}$

$\sqrt{2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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