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JEE Main 2019
9-01-2019 S1
Question
Let $0<\theta<\frac{\pi}{2}$. If the eccentricity of the hyperbola $\frac{x^2}{\cos ^2 \theta}-\frac{y^2}{\sin ^2 \theta}=1$ is greater than 2 , then the length of its latus rectum lies in the interval
Select the correct option:
A
(2, 3]
B
(3/2, 2]
C
(1, 3/2]
D
$(3, \infty)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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JEE Main
Mathematics
Hard
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