Let a, b and c be the length of sides of a triangle $A B C$ such that $\frac{a+b}{7}=\frac{b+c}{8}=\frac{c+a}{9}$. If $r$ and $R$ are the radius of in circle and radius of circumcircle of the triangle $A B C$, respectively, then the value of $\frac{R}{r}$ is equal to
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