Let ABC be a triangle..... | JEE Advanced 2010 | Mathematics

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JEE ADVANCE 2010

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Question

Let ABC be a triangle such that $\angle \mathrm{ACB}=\frac{\pi}{6}$ and let $\mathrm{a}, \mathrm{b}$ and c denote the lengths of the sides opposite to A , $B$ and $C$ respectively. The value(s) of $x$ for which $a=x^2+x+1, b=x^2-1$ and $c=2 x+1$ is (are)

Select the correct option:

A

$-(2+\sqrt{3})$

B

$1+\sqrt{3}$

C

$2+\sqrt{3}$

D

$4 \sqrt{3}$

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