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JEE MAIN 2025
08-04-25 S2
Question
Let $A=\left\{\theta \in[0,2 \pi]: 1+10 \operatorname{Re}\left(\frac{2 \cos \theta+i \sin \theta}{\cos \theta-3 i \sin \theta}\right)=0\right\}$. Then $\sum_{\theta \in \mathrm{A}} \theta^2$ is equal to
Select the correct option:
A
$\frac{27}{4} \pi^2$
B
$6 \pi^2$
C
$8 \pi^2$
D
$\frac{21}{4} \pi^2$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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Mathematics
Medium
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