Let f : R → (0, ∞) be twice.... | JEE Main 2026 | Continuity

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JEE MAIN 2026

21-01-2026 S1

Question

Let $f: \mathbf{R} \rightarrow(0, \infty)$ be a twice differentiable function such that $f(3)=18, f^{\prime}(3)=0$ and $f^{\prime \prime}(3)=4$. Then $\lim _{x \rightarrow 1}\left(\log _e\left(\frac{f(2+x)}{f(3)}\right)^{\frac{18}{(x-1)^2}}\right)$ is equal to :

Select the correct option:

A

1

B

9

C

2

D

18

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

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