Let be a given ellipse, length of whose| MAXIMA AND MINIMA

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JEE MAIN 2020

04-09-2020 S1

Question

Let $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1(a>b)$ be a given ellipse, length of whose latus rectum is 10 . If its eccentricity is the maximum value of the function, $\phi(t)=\frac{5}{12}+t-t^2$, then $a^2+b^2$ is equal to :

Select the correct option:

A

135

B

116

C

126

D

145

✓ Correct! Well done.

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