Let P(10, 2√15) be a point... | JEE Main 2026 22 Jan Shift 2

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JEE MAIN 2026

22-01-2026 S2

Question

Let $\mathrm{P}(10,2 \sqrt{15})$ be a point on the hyperbola $\frac{x^2}{\mathrm{a}^2}-\frac{y^2}{\mathrm{~b}^2}=1$, whose foci are S and $\mathrm{S}^{\prime}$. If the length of its latus rectum is 8 , then the square of the area of $\Delta \mathrm{PSS}^{\prime}$ is equal to:

Select the correct option:

A

2700

B

4200

C

900

D

1462

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

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