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JEE-Main 2024
06.04.24_(S1)
Question
Let $\mathrm{y}=\mathrm{y}(\mathrm{x})$ be the solution of the differential equation $\left(1+x^2\right) \frac{d y}{d x}+y=e^{\tan ^{-1} x}, \mathrm{y}(1)=0$. Then $\mathrm{y}(0)$ is $\_\_\_\_$ .
Select the correct option:
A
$\frac{1}{4}\left(\mathrm{e}^{\pi / 2}-1\right)$
B
$\frac{1}{2}\left(1-e^{\pi / 2}\right)$
C
$\frac{1}{4}\left(1-\mathrm{e}^{\pi / 2}\right)$
D
$\frac{1}{2}\left(\mathrm{e}^{\pi / 2}-1\right)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Easy
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