Let the maximum area of the... | ELLIPSE | JEE-Main 2022

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JEE MAIN 2022

24-06-2022 S2

Question

Let the maximum area of the triangle that can be inscribed in the ellipse $\frac{x^2}{a^2}+\frac{y^2}{4}=1, a>2$, having one of its vertices at one end of the major axis of the ellipse and one of its sides parallel to the y-axis, be$6 \sqrt{3}$ . Then the eccentricity of the ellipse is

Select the correct option:

A

$\frac{\sqrt{3}}{2}$

B

$\frac{1}{2}$

C

$\frac{1}{\sqrt{2}}$

D

$\frac{\sqrt{3}}{4}$

✓ Correct! Well done.

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Solution

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