Let $y=y(x)$ be solution of the differential equation $\log _e\left(\frac{d y}{d x}\right)=3 x+4 y$, with $y(0)=0$.
If $y\left(-\frac{2}{3} \log _e 2\right)=\alpha \log _e 2$, then the value of $\alpha$ is equal to :
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