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JEE MAIN 2019
12-01-2019 S1
Question
Let $y=y(x)$ be the solution of the differential equation, $x \frac{d y}{d x}+y=x \log _e x x,(x>1)$. If $2 y(2)=\log _e 4-1$, then $y(e)$ is equal to
Select the correct option:
A
(1) $\frac{e^2}{4}$
B
$-\frac{\mathrm{e}}{2}$
C
$-\frac{e^2}{2}$
D
$\frac{e}{4}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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