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JEE MAIN 2021
27-07-2021 S2
Question
Match List I with List II.
Select the correct option:
A
(a) → (iii), (b) → (ii), (c) → (iv), (d) → (i)
B
(a) → (iii), (b) → (iv), (c) → (ii), (d) → (i)
C
(a) → (iv), (b) → (ii), (c) → (iii), (d) → (i)
D
(a) → (iv), (b) → (iii), (c) → (ii), (d) → (i)
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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Solution
$$ q=C V $$ $$ \begin{aligned} & {[C]=\left[\frac{q}{V}\right]=\frac{(A \times T)^2}{M L^2 T^{-2}}} \\ & =M^{-1} L^{-2} T^4 A^2 \\ & {[E]=\left[\frac{F}{q}\right]=\frac{M L T^{-2}}{A T}} \\ & =M L T^{-3} A^{-1} \\ & F=\frac{q_1 q_2}{4 \pi \epsilon_0 r^2} \\ & {\left[\epsilon_0\right]=M^{-1} L^{-3} T^4 A^2} \end{aligned} $$ Speed of light $$ c=\frac{1}{\sqrt{\mu_0 \epsilon_0}} $$ $$ \begin{aligned} & \mu_0=\frac{1}{\epsilon_0 c^2} \\ & {\left[\mu_0\right]=\frac{1}{\left[M^{-1} L^{-3} T^4 A^2\right]\left[L^{-1}\right]^2}} \\ & =\left[M^1 L^1 T^{-2} A^{-2}\right] \end{aligned} $$
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