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JEE MAIN_2026
05-04-26_S1
Question
" P " is a hydrocarbon of molecular formula:- $\mathrm{C}_8 \mathrm{H}_{14}$. On ozonolysis, " P " forms "Q". "Q" on treatment with alkali under reflux condition produces " $R$ ", which on treatment with $I_2 / \mathrm{NaOH}$ gives a yellow precipitate. Acidification of the solution gives " S ". The structure of " S " is given below:- The correct structure of “P” is
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Showing 18 questions
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