Then the length of its | Ellipse

JEE-Main 2024

02-04-26_S1

Question

Let an ellipse $\frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{~b}^2}=1, \mathrm{a}<\mathrm{b}$, pass through the point $(4,3)$ and have eccentricity $\frac{\sqrt{5}}{3}$.Then the length of its latus rectum is :

Select the correct option:

$\frac{4 \sqrt{5}}{3}$

$2 \sqrt{5}$

$\frac{7 \sqrt{5}}{3}$

$\frac{8 \sqrt{5}}{3}$

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