Sol. Amount of solvent $=100-(29.25+19)=51.75 \mathrm{~g}$ $$ \begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\left[\frac{2 \times 29.25 \times 1000}{58.5 \times 51.75}+\frac{3 \times 19 \times 1000}{95 \times 51.75}\right] \times 0.52 \\ & \Delta \mathrm{~Tb}=16.075 \\ & \Delta \mathrm{~Tb}=\left(\mathrm{T}_{\mathrm{b}}\right)_{\text {solution }}-\left(\mathrm{T}_{\mathrm{b}}\right)_{\text {solvent }} \\ & =\left(\mathrm{T}_{\mathrm{b}}\right)_{\text {solution }}=100+16.07=116.07^{\circ} \mathrm{C} \end{aligned} $$