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JEE MAIN 2021
25-02-2021 S2
Question
$$ \text { If } I_n=\int_{\frac{\pi}{4}}^{\frac{\pi}{2}} \cot ^n x   d x, \text { then : } $$
Select the correct option:
A
$\frac{1}{I_2+I_4}, \frac{1}{I_3+I_5}, \frac{1}{I_4+I_6}$ are in G.P.
B
$I_2+I_4, I_3+I_5, I_4+I_6$ are in A.P.
C
$I_2+I_4,\left(I_3+I_5\right)_2, I_4+I_6$ are in G.P.
D
$\frac{1}{I_2+I_4}, \frac{1}{I_3+I_5}, \frac{1}{I_4+I_6}$ are in A.P.
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} I_n & =\int_{\pi / 4}^{\pi / 2} \cot ^n x d x=\int_{\pi / 4}^{\pi / 2} \cot ^{n-2} x\left(\operatorname{cosec}^2 x-1\right) d x \\ & \left.=-\frac{\cot ^{n-1} x}{n-1}\right]_{\pi / 4}^{\pi / 2}-I_{n-2} \\ & =\frac{1}{n-1}-I_{n-2} \\ & \Rightarrow \quad I_n+I_{n-2}=\frac{1}{n-1} \\ & \Rightarrow \quad I_2+I_4=\frac{1}{3} \\ & I_3+I_5=\frac{1}{4} \\ & I_4+I_6=\frac{1}{5} \\ & \quad \frac{1}{I_2+I_4}, \frac{1}{I_3+I_5}, \frac{1}{I_4+I_6} \text { are in A.P. }\end{aligned}$
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