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JEE MAIN 2019
10-04-2019 S2
Question
The angles $A, B$ and $C$ of a triangle $A B C$ are in A.P. and $a: b=1: \sqrt{3}$. If $c=4 \mathrm{~cm}$, then the area (in sq.cm) of this triangle is :
Select the correct option:
A
$\frac{2}{\sqrt{3}}$
B
$4 \sqrt{3}$
C
$2 \sqrt{3}$
D
$\frac{4}{\sqrt{3}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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