The capacitor of capacitance C can be charged (with the help of a resistance R ) by a voltage source V , by closing switch $\mathrm{S}_1$ while keeping switch $\mathrm{S}_2$ open. The capacitor can be connected in series with an inductor ' $L$ ' by closing switch $S_2$ and opening $S_1$.
Initially, the capacitor was uncharged. Now, switch $S_1$ is closed and $S_2$ is kept open. If time constant of this circuit is $\tau$, then
Select the correct option:
A
after time interval $\tau$, charge on the capacitor is CV/2
B
after time interval $2 \tau$, charge on the capacitor is $\operatorname{CV}\left(1-\mathrm{e}^{-2}\right)$
C
the work done by the voltage source will be half of the heat dissipated when the capacitor is fully charged.
D
after time interval $2 \tau$, charge on the capacitor is $\operatorname{CV}\left(1-\mathrm{e}^{-1}\right)$
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Initially, the capacitor was uncharged. Now, switch $S_1$ is closed and $S_2$ is kept open. If time constant of this circuit is $\tau$, then
