The electrostatic potential ( $\phi_{\mathrm{r}}$ ) of a spherical symmetric system, kept at origin, is shown in the adjacent figure, and given as
$$
\begin{array}{ll}
\phi_r=\frac{q}{4 \pi \epsilon_0 r} & \left(r \geq R_0\right) \\
\phi_r=\frac{q}{4 \pi \epsilon_0 R_0} & \left(r \leq R_0\right)
\end{array}
$$
Which of the following option(s) is/are correct?
Select ALL correct options:
A
For spherical region $\mathrm{r} \leq \mathrm{R}_0$, total electrostatic energy stored is zero.
B
Within $r=2 R_0$, total charge is $q$.
C
There will be no charge anywhere except at $\mathrm{r}=\mathrm{R}_0$.
D
Electric field is discontinuous at $\mathrm{r}=\mathrm{R}_0$.
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
The potential shown is for charged spherical conductor.
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇