The ellipse E₁ is inscribed.. |JEE Advanced 2012| Mathematics

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JEE ADVANCE 2012

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Question

The ellipse $E_1: \frac{x^2}{9}+\frac{y^2}{4}=1$ is inscribed in a rectangle $R$ whose sides are parallel to the coordinate axes. Another ellipse $E_2$ passing through the point $(0,4)$ circumscribes the rectangle $R$.. The eccentricity of the ellipse $E_2$ is

Select the correct option:

A

$\frac{\sqrt{2}}{2}$

B

$\frac{\sqrt{3}}{2}$

C

$\frac{1}{2}$

D

$\frac{3}{4}$

✓ Correct! Well done.

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