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JEE Advance 2023
Paper-2
Question
The entropy versus temperature plot for phases $\alpha$ and $\beta$ at 1 bar pressure is given. $\mathrm{S}_{\mathrm{t}}$ and $\mathrm{S}_0$ are entropies of the phases at temperatures T and 0 K , respectively. The transition temperature for $\alpha$ to $\beta$ phase change is 600 K and $C_{\mathrm{p} . \beta}-C_{\mathrm{p} . \mathrm{q}}=1 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$. Assume ( $C_{\mathrm{p} . \beta}$ $C_{\mathrm{p} . \mathrm{g}}$ ) is independent of temperature in the range of 200 to $700 \mathrm{~K} . C_{\mathrm{p} . \mathrm{q}}$ and $C_{\mathrm{p} . \beta}$ are heat capacities of $\alpha$ and $\beta$ phases, respectively.

The value of entropy change, $\mathrm{S}_\beta-\mathrm{Sa}$ (in $\mathrm{J} \mathrm{mol}^{-1} \mathrm{~K}^{-1}$ ), at 300 K is $\_\_\_\_$ [Use: In 2 = 0.69 Given: $\mathrm{S}_\beta-\mathrm{S}_{\mathrm{a}}=0$ at 0 K ]
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