Ellipse | JEE Main 2025 Solution | Chord with Given Midpoint

JEE Advanced 2025 - Mathematics

24-01-2025 SHIFT-2

Question

The equation of the chord, of the ellipse $\frac{x^{2}}{25}+\frac{y^{2}}{16}=1$, whose mid-point is $(3,1)$ is :

Select the correct option:

$4 x+122 y=134$

$5 x+16 y=31$

$48 x+25 y=169$

$25 x+101 y=176$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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