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JEE MAIN 2021
16-03-2021 S1
Question
The locus of the midpoints of the chord of the circle, $x^2+y^2=25$ which is tangent to the hyperbola, $\frac{x^2}{9}-\frac{y^2}{16}=1$ is :
Select the correct option:
A
$\left(x^2+y^2\right)^2-16 x^2+9 y^2=0$
B
$\left(x^2+y^2\right)^2-9 x^2+144 y^2=0$
C
$\left(x^2+y^2\right)^2-9 x^2-16 y^2=0$
D
$\left(x^2+y^2\right)^2-9 x^2+16 y^2=0$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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