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JEE Main 2024
06-04-2024 S2
Question
The number of electrons flowing per second in the filament of a 110 W bulb operating at 220 V is : (Given $\mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$ )
Select the correct option:
A
$31.25 \times 10^{17}$
B
$6.25 \times 10^{18}$
C
$6.25 \times 10^{17}$
D
$1.25 \times 10^{19}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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