The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line.
The readings of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is:
Select the correct option:
A
5.725 mm
B
5.740 mm
C
5.755mm
D
5.950 mm
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
LC = 0.5 / 100 = 0.005 mm
Zero error, e = −3 × 0.005 = −0.015 mm
Thickness = (5.5 + 48 × 0.005 − 0.015) mm
= 5.725 mm
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