The solubility product... |JEE Main 2023 | Ionic Equilibrium

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JEE MAIN 2023

08-04-2023 S2

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The solubility product of $\mathrm{BaSO}_4$ is $1 \times 10^{-10}$ at 298 K . The solubility of $\mathrm{BaSO}_4$ in 0.1 $\mathrm{M} \mathrm{K}_2 \mathrm{SO}_4(\mathrm{aq})$ solution is $\_\_\_\_$ $\times 10^{-9} \mathrm{~g} \mathrm{~L}^{-1}$ (nearest integer). Given : Molar mass of $\mathrm{BaSO}_4$ is $233 \mathrm{~g} \mathrm{~mol}^{-1}$

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