Two vertices of a triangle ABC are $\mathrm{A}(3,-1)$ and $\mathrm{B}(-2,3)$, and its orthocentre is $\mathrm{P}(1,1)$. If the coordinates of the point C are $(\alpha, \beta)$ and the centre of the circle circumscribing the triangle PAB is $(h, k)$, then the value of $(\alpha+\beta)+2(h+k)$ equals :
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