Let $P$ be a point in the plane of the vectors $\overrightarrow{A B}=3 \hat{i}+\hat{j}-\hat{k}$ and $\overrightarrow{A C}=\hat{i}-\hat{j}+3 \hat{k}$ such that $P$ is equidistant from the lines AB and AC. If $|\overrightarrow{A P}|=\frac{\sqrt{5}}{2}$, then the area of the triangle ABP is:
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