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JEE MAIN_2026
06-04-26_S1
Question
When 0.25 moles of a non-volatile, non-ionizable solute was dissolved in 1 mole of a solvent the vapour pressure of solution was $x \%$ of vapour pressure of pure solvent. What is $x \%$ ?
Select the correct option:
A
50%
B
60%
C
70%
D
80%
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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