$0.2 \%(\mathrm{w} / \mathrm{v})$ solution of NaOH is measured to have resistivity $870.0 \mathrm{~m} \Omega \mathrm{~m}$. The molar conductivity of the solution will be $\_\_\_\_$ $\times 10^{2} \mathrm{mS} \mathrm{dm} \mathrm{mol}^{-1}$. (Nearest integer)
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