JEE Main Integral Calculus PYQs 2024, 2025 and 2026: All Questions with Solutions
By CompetishunNov 03, 202629 min read
JEE Main Integral Calculus PYQs 2024, 2025 and 2026: All Questions with Solutions
Verified JEE Main Integral Calculus questions from 2024, 2025 and 2026, shift by shift. The 2024, 2025 and 2026 sets are interactive now: pick an option or enter a number and check instantly. Attempt timed, check the method only after answering, and log every miss by pattern.
Score: 0 correct out of 0 attempted ( interactive questions)
How to use this quiz
1. Attempt one year timed, without looking at the method.
2. Click an option, or type a number and press Check, for instant right or wrong feedback.
3. Read the short method only after answering, then log the miss by pattern.
4. Rework your weak patterns the same day, then reattempt the year.
2024 Questions (57)
Q127 Jan 2024, Shift 1
Orthocentre (a,b) of triangle (1,2),(2,3),(3,1); I1=∫ab x sin(4x-x2)dx, I2=∫ab sin(4x-x2)dx, find 36 I1I2.
Correct option: A. Method: Find a+b=4, apply King rule.
Answer: 155. Method: Split by integer values of the root.
Q1830 Jan 2024
y=f(x) thrice differentiable on (-5,5), tangents at (1,f(1)) and (3,f(3)) make angles π6 and π4 with positive x-axis, 27 ∫13 ((f'(t))2+1)f''(t)dt = α+β √3, α,β integers, find α+β.
Correct option: B. Method: Substitute u=f'(t), use tangent slopes.
Q1930 Jan 2024
f(x)=x2+3x+a for x≤1, bx+2 for x>1, differentiable on R, find ∫-22 f(x)dx.
Correct option: D. Method: Continuity and derivative match at x=1 give a,b. NOTE: video thumbnail labels it 300124 S2, card header shows no shift.
Q2030 Jan 2024
f(x)=x1+x41/4, g=f o f o f o f, find 18 ∫0√2√5 x2 g(x) dx.
Correct option: D. Method: Iterate f, simplify to x31+4x41/4.
Q2130 Jan 2024
Numerical: Area enclosed by parabola (y-2)2=x-1, line x-2y+4=0, and positive coordinate axes.
Answer: 5. Method: Integrate with respect to y, subtract line area.
Q2231 Jan 2024, Shift 1
Area of {(x,y): y2≤4x, x<4, xy(x-1)(x-2)(x-3)(x-4)>0, x not 3}.
Correct option: D. Method: Sign chart gives x in (0,1), double parabola area.
Q2331 Jan 2024, Shift 1
Numerical: 525 ∫0π/2 sin2x cos11/2x (1+cos5/2x)1/2 dx = n √2-64, find n.
Answer: 176. Method: Substitute cos x, simplify powers.
Q2431 Jan 2024, Shift 1
Numerical: f(x)=∫-1x (et-1)11 (2t-1)5 (t-2)7 (t-3)12 (2t-10)61 dt, p=sum of squares of local maxima x, q=sum of local minima x, find p2+2q.
Answer: 27. Method: Differentiate, sign chart of f'.
Q2531 Jan 2024, Shift 1
Numerical: f(x)=4x4x+2, a not 12, M=∫f(a)f(1-a) x sin4(x(1-x))dx, N=∫f(a)f(1-a) sin4(x(1-x))dx, α M=β N, α,β in N, least α2+β2.
Answer: 5. Method: Use f(a)+f(1-a)=1 and King rule.
Correct option: A. Method: Reduce cos4 to cos4x, cos2x.
Q341 Feb 2024, Shift 2
Numerical: F(x)=∫0x t f(t)dt, F(x2)=x4+x5, find Σr=112 f(r2).
Answer: 219. Method: Differentiate F, solve for f.
Q351 Feb 2024, Shift 2
Numerical: O(0,0), P(a,a2), Q(-b,b2), a>0,b>0 on y=x2, S1 area bounded by line PQ and parabola, S2 area of triangle OPQ, min S1S2 = mn, gcd=1, find m+n.
Answer: 7. Method: Chord area formula, minimise in ab.
Q361 Feb 2024, Shift 2
Numerical: Sum of squares of all possible k for which area bounded by parabolas 2y2=kx and ky2=2(y-x) is maximum.
Answer: 8. Method: Area as function of k, maximise.
Q374 Apr 2024, Shift 1
Curves y=1+3x-2x2 and y=1x, point (12,2) is an intersection, area = (124)(l √5+m)-n loge(1+√5), l,m,n in N, find l+m+n.
Correct option: B. Method: Other intersection 1+√52, integrate difference.
Q384 Apr 2024, Shift 1
Numerical: ∫0π/4 sin2x/(1+sinx cosx) dx = (1a)loge(a3)+πb √3, a,b in N, find a+b.
Answer: 8. Method: Split sin2, tan substitution. solution image truncated mid-calculation; a=2, b=6 is the completion.
Q394 Apr 2024, Shift 2
f(x)=∫0x (t+sin(1-et))dt, find limx→0f(x)x3.
Correct option: B. Method: L'Hopital three times / series expansion.
Q404 Apr 2024
Area of {(x,y): y2≤2x, y≥4x-1}.
Correct option: D. Method: Integrate with respect to y between intersections.
Q414 Apr 2024
∫-11cos(α x)1+3x dx = 2π, find a value of α.
Correct option: B. Method: Pair x with -x, integrate cos.
Q425 Apr 2024, Shift 1
∫0π/4 136 sin x3 sin x+5 cos x dx.
Correct option: A. Method: Combine numerator with denominator and derivative.
Q435 Apr 2024, Shift 1
∫-ππ 2y(1+sin y)1+cos2 y dy.
Correct option: A. Method: King rule, odd/even parts.
Q445 Apr 2024, Shift 1
Numerical: Area enclosed by y=x2-5x and y=7x-x2.
Answer: 72. Method: Intersections at 0,6, integrate difference.
Q455 Apr 2024, Shift 2
Area enclosed between y=x|x| and y=x-|x|.
Correct option: D. Method: Split at x=0, integrate difference on [-2,0].
Q465 Apr 2024, Shift 2
Beta(m,n)=∫01 xm-1(1-x)n-1dx, ∫01 (1-x10)20dx = a x Beta(b,c), find 100(a+b+c).
Correct option: D. Method: Substitute x10, Beta form. third variable renders ambiguously (looks like x); solution defines it as c=21.
Q476 Apr 2024, Shift 1
Area A enclosed by y=3x, 2y=27-3x, y=3x-x √x, find 10A.
Correct option: D. Method: Split at intersections, integrate.
Q486 Apr 2024, Shift 1
Numerical: rk=∫01 (1-x7)k dx / ∫01 (1-x7)k+1dx, k in N, find Σk=11017(rk-1).
Answer: 65. Method: Beta ratio gives rk-1=17(k+1).
Q498 Apr 2024, Shift 1
In = ∫01 (1-xk)n dx, n in N, 147 I20 = 148 I21, find k.
Correct option: D. Method: Use Beta/Γ ratio for consecutive In.
Let f(x) = 7 tan8 x + 7 tan6 x - 3 tan4 x - 3 tan2 x, I1 = ∫0π/4 f(x) dx and I2 = ∫0π/4 x f(x) dx. Then 7 I1 + 12 I2 is equal to:
Correct option: C. Method: Factor sec2x, substitute tan x, use integration by parts.
Q222 Jan 2025, Shift 1
Let f:R → R be a twice differentiable function such that f(x + y) = f(x) f(y) for all x, y in R, f'(0) = 4a, f''(x) - 3a f'(x) - f(x) = 0, a > 0. Then the area of the region R = {(x, y) | 0 ≤ y ≤ f(a x), 0 ≤ x ≤ 2} is:
Correct option: C. Method: Solve ODE for f, find a, integrate area.
Q322 Jan 2025, Shift 1
The area of the region inside the circle (x - 2 √3)2 + y2 = 12 and outside the parabola y2 = 2 √3 x is:
Correct option: C. Method: Subtract parabola area from semicircle area.
Q422 Jan 2025, Shift 2
Let f(x) = ∫0x2t2 - 8t + 15et dt, x in R. Then the numbers of local maximum and local minimum points of f, respectively, are:
Correct option: D. Method: Differentiate by Leibniz rule and examine sign changes.
Q522 Jan 2025, Shift 2
If ∫ ex (x - sin-1 x√1 - x2 + sin-1x1 - x23/2 + x1 - x2) dx = g(x) + C, then g(12) equals:
Correct option: D. Method: Recognize ex[f+f'] form and evaluate at 12.
Q622 Jan 2025, Shift 2
The area of the region enclosed by the curves y = x2 - 4x + 4 and y2 = 16 - 8x is:
Correct option: B. Method: Shift origin, apply standard parabola area formula.
Q723 Jan 2025, Shift 1
The value of ∫e2e4 (1x) [ e((loge x)2 + 1)-1 / ( e((loge x)2 + 1)-1 + e((6 - loge x)2 + 1)-1 ) ] dx is:
Correct option: A. Method: Substitute ln x=t and pair t with 6-t.
Q823 Jan 2025, Shift 1
If ∫ 3x + 4x2 (x - 2) dx = Ax + B log|x| + C log|x - 2| + ... [as printed, with a, b, c in a set whose symbol is blank/not rendered on the card], then 3(b + c) equals:
Correct option: B. Method: Substitute x-11x+15 and integrate termwise.
Q923 Jan 2025, Shift 1
If the area of the larger portion bounded between the curves x2 + y2 = 25 and y = |x - 1| is 14 (b π + c), b, c in [set symbol blank/not rendered on card], then b + c equals ............
Answer: 77. Method: Add circle segment and triangle areas, then combine.
Q1023 Jan 2025, Shift 2
If the area of the region {(x, y): -1 ≤ x ≤ 1, 0 ≤ y ≤ a + e|x| - e-x, a > 0} is e2 + 8e + 1e, then the value of a is:
Correct option: B. Method: Integrate exponential pieces split at zero, solve for a.
Q1123 Jan 2025, Shift 2
Let ∫ x3 sin x dx = g(x) + C. If 8(g(π2) + g'(π2)) = α π3 + β π2 + γ, α, β, γ in Z, then α + β - γ equals:
Correct option: C. Method: Repeated integration by parts, then evaluate at π2.
Q1223 Jan 2025, Shift 2
If I = ∫0π/2 sin3/2 x / (sin3/2 x + cos3/2 x) dx, then ∫02I x sin x cos x / (sin4 x + cos4 x) dx equals:
Correct option: A. Method: Upper limit is 2I, where I = π4; apply King property, then substitute tan2x.
Q1324 Jan 2025, Shift 1
The area of the region {(x, y): x2 + 4x + 2 ≤ y ≤ |x + 2|} is equal to:
Correct option: C. Method: Shift curve, integrate difference with absolute line.
Q1424 Jan 2025, Shift 1
Let f be a differentiable function such that 2(x + 2)2 f(x) - 3(x + 2)2 = 10 ∫0x (t + 2) f(t) dt, x ≥ 0. Then f(2) is equal to ____.
Answer: 19. Method: Differentiate, solve linear ODE, evaluate at 2.
Q1524 Jan 2025, Shift 2
The area of the region enclosed by the curves y = ex, y = |ex - 1| and the y-axis is:
Correct option: A. Method: Integrate with respect to y between exponential curves.
Q1624 Jan 2025, Shift 2
If ∫ 2x2 + 5x + 9√x2 + x + 1 dx = x √x2 + x + 1 + α √x2 + x + 1 + β loge |x + 12 + √x2 + x + 1| + C, then α + 2 β is equal to ____
Answer: 16. Method: Split numerator using derivative of denominator, then integrate.
Q1724 Jan 2025
If I(m, n) = ∫01 xm-1 (1 - x)n-1 dx, m, n > 0, then I(9, 14) + I(10, 13) is:
Correct option: D. Method: Substitute x=sin2 θ and combine the two integrals.
Q1828 Jan 2025, Shift 1
Let, for some function y = f(x), ∫0x t f(t) dt = x2 f(x), x > 0 and f(2) = 3. Then f(6) is equal to:
The area, in sq. units, of the region {(x, y): 0 ≤ y ≤ 2|x| + 1, 0 ≤ y ≤ x2 + 1, |x| ≤ 3} is:
Correct option: C. Method: Use symmetry and split ∫ at intersections.
Q2028 Jan 2025, Shift 1
If ∫-π/2π/296 x2 cos2 x1 + ex dx = π (α π2 + β), α, β in [set symbol blank/not rendered on card], then (α + β)2 equals:
Correct option: B. Method: Apply King property and compare coefficients.
Q2128 Jan 2025, Shift 2
Let f be a real-valued continuous function defined on the positive real axis such that g(x) = ∫0x t f(t) dt. If g(x3) = x6 + x7, then the value of sum from r = 1 to 15 f(r3) is:
Correct option: B. Method: Differentiate g(x3) to find f, then sum values.
Q2228 Jan 2025, Shift 2
Let f:R → R be a twice differentiable function such that f(2) = 1. If F(x) = x f(x) for all x in R, ∫02 x F'(x) dx = 6 and ∫02 x2 F''(x) dx = 40, then F'(2) + ∫02 F(x) dx is equal to:
Correct option: B. Method: Integrate by parts twice using given integrals.
Q2328 Jan 2025, Shift 2
The area of the region bounded by the curves x(1 + y2) = 1 and y2 = 2x is:
Correct option: B. Method: Integrate with respect to y using symmetry.
Q2428 Jan 2025, Shift 2
If f(x) = ∫ 1x1/4(1 + x1/4) dx, f(0) = -6, then f(1) is equal to:
Correct option: D. Method: Substitute x=t4 and simplify logarithmic terms.
Q2529 Jan 2025, Shift 1
Let the area of the region {(x, y): 2y ≤ x2 + 3, y + |x| ≤ 3, y ≥ |x - 1|} be A. Then 6A is equal to:
Correct option: A. Method: Subtract parabola segment from enclosing rectangle.
Q2629 Jan 2025, Shift 1
The ∫ 80 ∫0π/4sin θ + cos θ9 + 16 sin 2θ d θ is equal to:
Correct option: D. Method: Substitute sin θ-cos θ and evaluate log limits.
Q2729 Jan 2025, Shift 1
Let f:(0, ∞) → R be a twice differentiable function. If, for some a ≠ 0, ∫01 f(λ x) d λ = a f(x), f(1) = 1 and f(16) = 18, then 16 - f'(116) is equal to ______.
Let f(x) = ∫0x t(t2 - 9t + 20) dt, 1 ≤ x ≤ 5. If the range of f is [α, β], then 4(α + β) equals:
Correct option: D. Method: Differentiate by Leibniz rule, check endpoints and critical points.
Q2929 Jan 2025, Shift 2
Let the area enclosed between the curves |y| = 1 - x2 and x2 + y2 = 1 be α. If 9 α = β π + γ; β, γ are integers, then the value of |β - γ| equals:
Correct option: C. Method: Subtract parabola area from circle quadrant area.
Q3029 Jan 2025, Shift 2
If 24 ∫0π/4 ( sin|4x - π12| + [2 sin x] ) dx = 2 π + α, where [.] denotes the greatest integer function, then α is equal to ____.
Answer: 12. Method: Split ∫ where greatest-integer value changes.
Q312 Apr 2025, Shift 1
If the area of the region {(x, y): |4 - x2| ≤ y ≤ x2, y ≤ 4, x ≥ 0} is (80 √2 / α - β), α, β in N, then α + β = ____.
Answer: 22. Method: Integrate with respect to y, add segment areas.
Q322 Apr 2025, Shift 1
Let [.] denote the greatest integer function. If ∫0e3 [1ex - 1] dx = α - loge 2, then α3 is equal to _____.
Answer: 8. Method: Split ∫ at greatest-integer breakpoints and sum.
Q332 Apr 2025, Shift 2
Let (a, b) be the point of intersection of the curve x2 = 2y and the straight line y - 2x - 6 = 0 in the second quadrant. Then the ∫ I = ∫ab9x21 + 5x dx is equal to:
Correct option: A. Method: Find second-quadrant intersection, pair exponential terms.
Q342 Apr 2025, Shift 2
Let f:[1, ∞) → [2, ∞) be a differentiable function. If 10 ∫1x f(t) dt = 5x f(x) - x5 - 9 for all x ≥ 1, then the value of f(3) is:
Correct option: B. Method: Differentiate, solve linear ODE, evaluate at 3.
Q352 Apr 2025, Shift 2
4 ∫011√3 + x2 + √1 + x2 dx - 3 loge (√3) is equal to:
Correct option: B. Method: Rationalize denominator and integrate square-root terms.
Q363 Apr 2025, Shift 1
Let f(x) = ∫ x3 √3 - x2 dx. If 5 f(√2) = -4, then f(1) is equal to:
Correct option: C. Method: Substitute 3-x2=t2 and use given condition.
Q373 Apr 2025, Shift 1
The area of the region bounded by the curve y = max{|x|, x|x - 2|}, the x-axis and the lines x = -2 and x = 4 is equal to ____.
Answer: 12. Method: Split maximum function pieces and add triangle areas.
Q383 Apr 2025, Shift 2
The ∫ ∫0π 8x dx / (4 cos2 x + sin2 x) is equal to:
Correct option: B. Method: Apply King property, divide by cos2x, substitute tan x.
Q394 Apr 2025, Shift 1
The value of ∫-11 [ (1 + √|x| - x) ex + √|x| - x e-x ] / (ex + e-x) dx is equal to:
Correct option: A. Method: Apply King property and simplify absolute terms.
Q404 Apr 2025, Shift 1
If the area of the region {(x, y): |x - 5| ≤ y ≤ 4 √x} is A, then 3A is equal to ____.
Answer: 368. Method: Integrate parabola area minus triangular pieces.
Q414 Apr 2025, Shift 2
A line passing through the point A(-2, 0) touches the parabola P: y2 = x - 2 at the point B in the first quadrant. The area of the region bounded by the line AB, the parabola P and the x-axis is:
Correct option: B. Method: Find tangent point by discriminant, integrate with respect to y.
Q424 Apr 2025, Shift 2
Let f(x) + 2 f(1x) = x2 + 5 and 2 g(x) - 3 g(12) = x, x > 0. If α = ∫12 f(x) dx and β = ∫12 g(x) dx, then the value of 9 α + β is:
Correct option: A. Method: Solve f and g functional equations, then integrate.
Q437 Apr 2025, Shift 1
If the area of the region bounded by the curves y = 4 - x24 and y = x - 42 is α, then 6 α equals:
Correct option: A. Method: Integrate parabola minus line, multiply result by six.
Q447 Apr 2025, Shift 1
The ∫ ∫0π (x + 3) sin x / (1 + 3 cos2 x) dx is equal to:
Correct option: D. Method: Apply King property, substitute √3 cos x.
Q457 Apr 2025, Shift 2
If the area of the region {(x, y): 1 + x2 ≤ y ≤ min{x + 7, 11 - 3x}} is A, then 3A is equal to:
Correct option: D. Method: Split at min-function crossover, integrate pieces.
Q467 Apr 2025, Shift 2
If ∫ (1x + 1x3)(cube root of (3x-24 + x-26)) dx = -α3(α + 1) (3xβ + x7)(α + 1)/γ + C, x > 0, then α + β + γ is equal to ____.
Answer: 19. Method: Substitute bracketed expression, match coefficients, add α+β+γ.
Q478 Apr 2025, Shift 2
The ∫ ∫-13/2 |π2 - x sin(π x)| dx is equal to:
Correct option: C. Method: Split absolute value, integrate by parts.
Q488 Apr 2025, Shift 2
Let f(x) be a positive function and I1 = ∫-1/21/2 2x f(2x(1 - 2x)) dx and I2 = ∫-12 f(x(1 - x)) dx. Then the value of I2I1 is equal to ____.
Correct option: C. Method: Substitute t=1-x to relate I2 to I1.
Answer: 16. Method: Substitute t=cot x; integrate powers term by term.
Q1022 Jan 2026, Shift 2
Area of A={(x,y): 4x2+y2≤8 and y2≤4x} is ?
Correct option: B. Method: Integrate parabola part plus ellipse segment.
Q1122 Jan 2026, Shift 2
Let [.] be greatest integer. If α=∫064 (x(1/3)-[x(1/3)]) dx, then (1π) ∫0απ (sin2θsin6 θ+cos6 θ) d θ = ?
Answer: 36. Method: Evaluate α by intervals; use periodicity and King property.
Q1223 Jan 2026, Shift 1
Let f(x)=∫ (2-x2)ex√1+x(1-x)(3/2) dx. If f(0)=0, then f(12) = ?
Correct option: A. Method: Rewrite integrand in ex(f+f') form and integrate.
Q1323 Jan 2026, Shift 1
Value of ∫π/245π/24dx1+cuberoot(tan 2x) is ?
Correct option: A. Method: Use x → (π6)-x; add paired integrals.
Q1423 Jan 2026, Shift 1
Let area bounded by y=max{sin x, cos x}, x=0, x=3π2 and x-axis be A. Then A+A2 = ?
Answer: 12. Method: Split at π4 and 5π4; integrate max curve.
Q1523 Jan 2026, Shift 1
Let f be twice differentiable, non-negative, with (f(x))2=25+∫0x ((f(t))2+(f'(t))2) dt. Mean of f(loge 1), f(loge 2), ..., f(loge 625) is ?
Answer: 1565. Method: Differentiate twice; get f=5ex; average 5k.
Q1623 Jan 2026, Shift 2
Let I(x)=∫ 3 dx(4x+6)√4x2+8x+3 and I(0)=√34+20. If I(12)=a √2b + c, a,b,c in N, gcd(a,b)=1, then a+b+c = ?
Correct option: C. Method: Substitute for √(4x+2)/(4x+6); use I(0).
Q1723 Jan 2026, Shift 2
Number of elements in S={x in [0,100]: ∫0x t2 sin(x-t) dt = x2} is ?
Answer: 16. Method: Differentiate twice; solve cos x equation in range.
Q1824 Jan 2026, Shift 1
Let f(t)=∫ (1-sin(loge t)1-cos(loge t)) dt, t>1. If f(e(π/2))=e(π/2) and f(e(π/4))=α e(π/4), then α = ?
Correct option: A. Method: Use cot(t2) form; evaluate at π8.
Q1924 Jan 2026, Shift 1
Let A1 be bounded area enclosed by y=x2+2, x+y=8 and y-axis in first quadrant; A2 be bounded area enclosed by y=x2+2, y2=x, x=2 and y-axis in first quadrant. Then A1-A2 = ?
Correct option: A. Method: Subtract integrals; intersection at (2,6).
Q2024 Jan 2026, Shift 2
If f(x)=ex+∫01 (y+x ex) f(y) dy, then e+f(0) = ?
Answer: 2. Method: Set constants A=∫ f, B=∫ y f(y); solve linear equations.
Q2128 Jan 2026, Shift 1
If ∫ (1-5 cos2 xsin5 x cos2 x) dx = f(x)+C, then f(π6)-f(π4) = ?
Correct option: B. Method: Divide by cos2 x; set t=tan x.
Q2228 Jan 2026, Shift 1
Area of R={(x,y): xy≤8, 1≤y≤x2, x≥0} is ?
Correct option: C. Method: Split at x=2; integrate x2 and 8x.
Q2328 Jan 2026, Shift 2
Let [.] be greatest integer. Value of ∫-π/2π/2 123+[x]3+[sin x]+[cos x] dx is ?
Correct option: A. Method: Split by integer parts; pair symmetric intervals.
Q2428 Jan 2026, Shift 2
Let f(x)=∫ dxx(2/3)+2 x(1/2). If f(0)=-26+24 loge 2 and f(1)=a+b loge 3, then a+b = ?
Correct option: A. Method: Put x=t6; integrate and use f(0).
Q2528 Jan 2026, Shift 2
Let f be a polynomial with f(x2+1)=x4+5x2+2 for all real x. Then ∫03 f(x) dx is ?
Correct option: B. Method: Identify f(t)=t2+3t-2; integrate 0 to 3.
Q2628 Jan 2026, Shift 2
Value of Σr=120 √π∫0r x|sin π x| dx is ?
Answer: 210. Method: Evaluate each ∫ as r2π; sum 1 to 20.
Q2728 Jan 2026, Shift 2
Let f be differentiable with f(x)=1-2x+∫0x ex-t f(t) dt, and g(x)=∫0x (f(t)+2)15 (t-4)6 (t+12)17 dt. If p is sum of local minima and q sum of local maxima of g, then |p+q| = ?
Answer: 9. Method: Find f+2=ex; sign changes of g' at -12 and 3.
Q282 Apr 2026, Shift 1
Let [.] be greatest integer. Value of ∫03ex+e-xx! dx is ?
Correct option: B. Method: Split [0,1),[1,2),[2,3); integrate ex+e-x.
Q292 Apr 2026, Shift 1
If α=∫02 √3 log2(x2+4) dx + ∫24 √2x-4 dx, then α2 = ?
Answer: 192. Method: Use inverse-function ∫ property; α=8 √3.
Q302 Apr 2026, Shift 2
Value of ∫020π (sin4 x+cos4 x) dx is ?
Correct option: C. Method: Use sin4+cos4=34+(14)cos 4x; period π.
Q312 Apr 2026, Shift 2
Let f(x)=∫ 16x+24x2+2x-15 dx. If f(4)=14 loge 3 and f(7)=loge(2α x 3β), α,β in N, then α+β = ?
Correct option: C. Method: Split into log derivative plus partial fractions.
Q322 Apr 2026, Shift 2
If area bounded by 16x2-9y2=144 and 8x-3y=24 is A, then 3(A+6 loge 3) = ?
Answer: 24. Method: Integrate hyperbola branch against line; simplify logs.
Q334 Apr 2026, Shift 1
Let [.] be greatest integer. If ∫-22 (|sin x|+[x sin x]) dx = 2(3-cos 2)+β, then β sin(β2) = ?
Correct option: B. Method: Split at 0; evaluate [x sin x] intervals.
Q344 Apr 2026, Shift 2
Area bounded by curves x+3y2=0 and x+4y2=1 is ?
Correct option: C. Method: Integrate in y between parabolas.
Q354 Apr 2026, Shift 2
∫01 cot-1(1+x+x2) dx is ?
Correct option: D. Method: Write as tan-1 difference; integrate by parts.
Q365 Apr 2026, Shift 1
Area of R={(x,y): xy≤27, 1≤y≤x2} is ?
Correct option: B. Method: Split at x=3; integrate x2 and 27x.
Q375 Apr 2026, Shift 1
Value of ∫0∞loge xx2+4 dx is ?
Correct option: B. Method: Substitute x=2t; use known log ∫.
Q385 Apr 2026, Shift 1
Value of ∫π/6π/3 (4-cosec2 x)/cos4 x dx is ?
Correct option: C. Method: Divide by cos4 x; set t=tan x.
Q395 Apr 2026, Shift 2
Let (21-a+21+a), f(a), (3a+3-a) be in AP, and α be the minimum value of f(a). Then ∫log(α-1)log(α)dxe2x-e-2x is ?
Correct option: B. Method: Find α=4 by AM-GM; substitute t=e2x.
Q405 Apr 2026, Shift 2
Let f:R→R satisfy f(x)+3f(π2-x)=sin x. Let maximum value of f on R be α. If area bounded by g(x)=x2 and h(x)=β x3, β>0, is α2, then 30 β3 = ?
Answer: 16. Method: Solve functional equation; area gives β.
Q416 Apr 2026, Shift 1
Let f:[1,∞)→R be differentiable, defined as f(x)=∫1x f(t) dt + (1-x)(loge x-1)+e. Then f(f(1)) is ?
Correct option: A. Method: Differentiate; get f(x)=(1-x)(ln x-1)+e.
Q426 Apr 2026, Shift 1
Value of ∫-π/4π/432 cos4 x1+esin x dx is ?
Correct option: B. Method: Use x → -x; add paired integrals.
Q436 Apr 2026, Shift 1
Area of {(x,y): 0≤y≤6-x, y2≥4x-3, x≥0} is ?
Correct option: B. Method: Integrate line minus parabola region in y.
Q446 Apr 2026, Shift 2
Area of {(x,y): x2-8x≤y≤-x} is ?
Correct option: A. Method: Integrate (7x-x2) from 0 to 7.
Q456 Apr 2026, Shift 2
Value of ∫-11x3+|x|+1x2+2|x|+1 dx is ?
Correct option: B. Method: Odd part cancels; use even part and partial fractions.
Q468 Apr 2026, Shift 2
Value of ∫02 √xx2+x+1(√x+1)√x4+x2+1 dx is ?
Correct option: C. Method: Put x=t2; simplify to 1√t2+1 form.
Q478 Apr 2026, Shift 2
Let f:(1,∞)→R, f(x)=x-1x+1, fi+1=f(fi), i=1,...,25, f1=f. If g+f26=0 on (1,∞), then area bounded by y=g(x), 2y=2x-3, y=0, x=4 is ?
Correct option: A. Method: Iterate f to get g=1x; integrate plus triangle.
Q488 Apr 2026, Shift 2
If ∫π/6π/4 (cot(x-π3)cot(x+π3)+1) dx = α loge(√3-1), then 9 α2 = ?
Answer: 12. Method: Simplify cot product to cosec2 form; integrate.
JEE MAIN 2027
JEE Main 5 Years Mathematics PYQ Book 2022-2026
Chapter-wise solved papers with detailed solutions.
Pick an option for a multiple choice question, or type your answer for a numerical question and press Check. A correct choice turns green, a wrong choice turns red and the correct option turns green, and the short method appears below. Once answered, a card locks until you press Reset.
How many Integral Calculus questions are in this quiz, and from which years?
153 verified JEE Main Integral Calculus questions: 57 from 2024, 48 from 2025 and 48 from 2026, each in shift order.
How should I use this quiz for revision?
Attempt one year timed, without looking at the method. After checking, note every miss by pattern, such as indefinite integration, definite integration, or area under a curve, and rework that pattern the same day.
Why do some questions ask for a value instead of options?
Those are numerical questions from the paper itself, where the answer is a number, not a choice. Type the number and press Check; the check ignores units, spaces and case, with a small tolerance.
Are these real JEE Main questions?
Yes. Every question here is a verified JEE Main Integral Calculus question from 2024, 2025 or 2026, shown with its shift.
Tags
JEE Main 2027Integral Calculus PYQJEE Main MathsPYQ AnalysisRepeat FrequencyUPO Unique PYQsIndefinite IntegrationDefinite IntegrationArea Under CurveJEE Main Preparation
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