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JEE Main Differential Equations PYQs 2024, 2025 and 2026: All Questions with Solutions

By Competishun Nov 03, 2026 19 min read

JEE Main Differential Equations PYQs 2024, 2025 and 2026: All Questions with Solutions

Verified JEE Main Differential Equations questions from 2024, 2025 and 2026, shift by shift. The 2024, 2025 and 2026 sets are interactive now: pick an option or enter a number and check instantly. Attempt timed, check the method only after answering, and log every miss by pattern.

Score: 0 correct out of 0 attempted ( interactive questions)

How to use this quiz

1. Attempt one year timed, without looking at the method.

2. Click an option, or type a number and press Check, for instant right or wrong feedback.

3. Read the short method only after answering, then log the miss by pattern.

4. Rework your weak patterns the same day, then reattempt the year.

2024 Questions (34)

Q127 Jan 2024, Shift 1

If the solution of the differential equation (2x + 3y − 2) dx + (4x + 6y − 7) dy = 0, y(0) = 3, is αx + βy + 3 loge|2x + 3y − γ| = 6, then α + 2β + 3γ is equal to

Q227 Jan 2024, Shift 1

Let x = x(t) and y = y(t) be solutions of the differential equations dx/dt + ax = 0 and dy/dt + by = 0 respectively, a, b ∈ R. Given that x(0) = 2, y(0) = 1 and 3y(1) = 2x(1), the value of t, for which x(t) = y(t), is

Q327 Jan 2024, Shift 2

If the solution curve, of the differential equation dy/dx = (x + y − 2)/(x − y) passing through the point (2, 1) is tan−1((y−1)/(x−1)) − (1/β) loge(α + ((y−1)/(x−1))2) = loge|x−1|, then 5β + α is equal to

Q427 Jan 2024, Shift 2

If y = y(x) is the solution curve of the differential equation (x2 − 4) dy − (y2 − 3y) dx = 0, x > 2, y(4) = 3/2 and the slope of the curve is never zero, then the value of y(10) equals

Q529 Jan 2024, Shift 1

If the solution curve y = y(x) of the differential equation (1 + y2)(1 + loge x) dx + x dy = 0, x > 0 passes through the point (1, 1) and y(e) = (α − tan(3/2))/(β + tan(3/2)), then α + 2β is

Q629 Jan 2024, Shift 1

A function y = f(x) satisfies f(x) sin 2x + sin x − (1 + cos2 x) f'(x) = 0 with condition f(0) = 0. Then, f(π/2) is equal to

Q729 Jan 2024, Shift 2

Let f(x) = √limr→x { 2r2[(f(r))2 − f(x)f(r)]/(r2 − x2) − r3 ef(r)/r } be differentiable in (−∞, 0) ∪ (0, ∞) and f(1) = 1. Then the value of ea, such that f(a) = 0, is equal to

Q829 Jan 2024, Shift 2

If sin(y/x) = loge|x| + α/2 is the solution of the differential equation x cos(y/x) dy/dx = y cos(y/x) + x and y(1) = π/3, then α2 is equal to

Q930 Jan 2024, Shift 1

Let y = y(x) be the solution of the differential equation (1 − x2) dy = [xy + (x3 + 2)√3(1 − x2)] dx, −1 < x < 1, y(0) = 0. If y(1/2) = m/n, m and n are coprime numbers, then m + n is equal to

Q1030 Jan 2024, Shift 1

Let y = y(x) be the solution of the differential equation sec x dy − (2 sin x tan x + y) dx = 0 such that y(0) = 2. Then y(2) is equal to

Q1130 Jan 2024, Shift 2

Let Y = Y(X) be a curve lying in the first quadrant such that the area enclosed by the line Y - y = Y'(x)(X - x) and the co-ordinate axes, where (x, y) is any point on the curve, is always -y2 / (2Y'(x)) + 1, Y'(x) ≠ 0. If Y(1) = 1, then 12Y(2) is equal to

Q1231 Jan 2024, Shift 1

The solution curve of the differential equation y dx/dy = x(loge x − loge y + 1), x > 0, y > 0 passing through the point (e, 1) is

Q1331 Jan 2024, Shift 1

Let y = y(x) be the solution of the differential equation dy/dx = ((tan x) + y)/(sin x (sec x − sin x tan x)), x ∈ (0, π/2) satisfying the condition y(π/4) = 2. Then, y(π/3) is

Q1431 Jan 2024, Shift 2

The temperature T(t) of a body at time t = 0 is 160°F and it decreases continuously as per the differential equation dT/dt = −k(T − 80), where k is positive constant. If T(15) = 120°F, then T(45) is equal to

Q1531 Jan 2024, Shift 2

Let y = y(x) be the solution of the differential equation sec2 x dx + (e2y tan2 x + tan x) dy = 0, 0 < x < π/2, y(π/4) = 0. If y(π/6) = α, then e8α is equal to ___

Q161 Feb 2024, Shift 1

If x = x(t) is the solution of the differential equation (t + 1) dx = (2x + (t + 1)4) dt, x(0) = 2, then x(1) equals

Q171 Feb 2024, Shift 1

Let y = y(x) be the solution of the differential equation dy/dx = 2x(x + y3)/(xy − 1), y(0) = 1. Then (1/√2 + y(1/√2))2 equals

Q184 Apr 2024, Shift 1

Let the solution y = y(x) of the differential equation dy/dx − y = 1 + 4 sin x satisfy y(π) = 1. Then y(π/2) + 10 is equal to

Q194 Apr 2024, Shift 1

If the solution y = y(x) of the differential equation (x4 + 2x3 + 3x2 + 2x + 2) dy − (2x2 + 2x + 3) dx = 0 satisfies y(−1) = −π/4, then y(0) is equal to

Q204 Apr 2024, Shift 2

Let y = y(x) solve (x + y + 2)2 dx = dy, y(0) = −2. Let α, β be the maximum and minimum of y(x) on [0, π/3]. If (3α + π)2 + β2 = γ + δ√3, γ, δ integers, then γ + δ equals

Q214 Apr 2024, Shift 2

Let y = y(x) be the solution of the differential equation (x2 + 4)2 dy + (2x3 y + 8xy − 2) dx = 0. If y(0) = 0, then y(2) is equal to

Q225 Apr 2024, Shift 1

Let f be a differentiable function in the interval (0, ∞) such that f(1) = 1 and limt→x (t2 f(x) − x2 f(t))/(t − x) = 1 for each x > 0. Then 2f(2) + 3f(3) is equal to

Q235 Apr 2024, Shift 1

If y = y(x) is the solution of the differential equation dy/dx + 2y = sin 2x, y(0) = 3/4, then y(π/8) is equal to

Q245 Apr 2024, Shift 2

Let y = y(x) be the solution of the differential equation dy/dx = 2x/(1 + x2)2 − y e1/(1 + x2), y(0) = 0. Then the area enclosed by the curve f(x) = y(x) e1/(1 + x2) and the line y − x = 4 is ____.

Q255 Apr 2024, Shift 2

The differential equation of the family of circles passing the origin and having center at the line y = x is

Q266 Apr 2024, Shift 1

A conic C passes through (4, −2). At any point P(x, y), x ≥ 3, on C, the tangent slope is half the slope of the line joining P to (3, −5). If the focal distance of (7, 1) on C is d, then 12d equals ____.

Q276 Apr 2024, Shift 1

Let y = y(x) be the solution of the differential equation (2 + x loge x) dy/dx + 2y = 3x loge x, x > 0 and y(e−1) = 0. Then, y(e) is equal to ____.

Q286 Apr 2024, Shift 1

Let y = y(x) be the solution of the differential equation (1 + x2) dy/dx + y = etan−1 x, y(1) = 0. Then y(0) is ____.

Q298 Apr 2024, Shift 1

Let y = y(x) be the solution of the differential equation (1 + y2) etan x dx − cos2 x (1 + e2 tan x) dy = 0, y(0) = 1. Then y(π/4) is equal to

Q308 Apr 2024, Shift 1

Let f(x) be positive such that the area bounded by y = f(x), y = 0, from x = 0 to x = a > 0 is e−a + 4a2 + a − 1. The differential equation whose general solution is y = c1f(x) + c2 is

Q319 Apr 2024, Shift 1

The solution of the differential equation (x2 + y2) dx − 5xy dy = 0, y(1) = 0 is

Q329 Apr 2024, Shift 1

The solution curve of the differential equation 2y dy/dx + 3 = 5 dy/dx passing through the point (0, 1) is a conic whose vertex lies on the line

Q339 Apr 2024, Shift 2

For a differentiable function f: R → R, suppose f'(x) = 3 f(x) + α, where α ∈ R, f(0) = 1 and limx→−∞ f(x) = 7. Then 9 f(−loge 3) is equal to

Q349 Apr 2024, Shift 2

Let ∫0x √1 − (y'(t))2 dt = ∫0x y(t) dt, 0 ≤ x ≤ 3, y ≥ 0, y(0) = 0. Then at x = 2, y'' + y + 1 is equal to :

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2025 Questions (17)

Q122 Jan 2025, Shift 2

If x = f(y) is the solution of the differential equation (1 + y2) + (x - 2e(tan-1 y)) dy/dx = 0, y ∈ (-π/2, π/2) with f(0) = 1, then f(1/√3) is equal to:

Q223 Jan 2025, Shift 1

Let a curve y = f(x) pass through the points (0, 5) and (loge 2, k). If the curve satisfies the differential equation 2(3 + y) e(2x) dx - (7 + e(2x)) dy = 0, then k is equal to:

Q323 Jan 2025, Shift 2

Let x = x(y) be the solution of the differential equation y = (x - y dx/dy) sin(x/y), y > 0 and x(1) = π/2. Then cos(x(2)) is equal to:

Q424 Jan 2025, Shift 1

Let y = y(x) be the solution of the differential equation (xy - 5x2 √1 + x2) dx + (1 + x2) dy = 0, y(0) = 0. Then y(√3) is equal to:

Q524 Jan 2025, Shift 2

Let y = y(x) be the solution of the differential equation 2 cos x dy/dx + sin 2x - 4y sin x = 0, x ∈ (0, π/2). If y(π/3) = 0, then y'(π/4) + y(π/4) is equal to:

Q628 Jan 2025, Shift 2

If y = y(x) is the solution of the differential equation √4 - x2 dy/dx = ((sin-1(x/2))2 - y) sin-1(x/2), -2 ≤ x ≤ 2, y(2) = (π2 - 8)/4, then y2(0) is equal to:

Q729 Jan 2025, Shift 1

Let y = y(x) be the solution of the differential equation cos x (loge (cos x))2 dy + (sin x - 3y sin x loge (cos x)) dx = 0, x ∈ (0, π/2). If y(π/4) = -1/loge 2, then y(π/6) is equal to:

Q829 Jan 2025, Shift 2

If for the solution curve y = f(x) of the differential equation dy/dx + (tan x) y = (2 + sec x)/(1 + 2 sec x)2, x ∈ (-π/2, π/2), f(π/3) = √3/10, then f(π/4) is equal to:

Q92 Apr 2025, Shift 1

Let f: R → R be a thrice differentiable odd function satisfying f'(x) ≥ 0, f''(x) = f(x), f(0) = 0, f'(0) = 3. Then 9f(loge 3) is equal to ______.

Q102 Apr 2025, Shift 2

Let y = y(x) be the solution of the differential equation dy/dx + 2y sec2 x = 2 sec2 x + 3 tan x · sec2 x such that y(0) = 5/4. Then 12(y(π/4) - e(-2)) is equal to ____.

Q113 Apr 2025, Shift 1

Let g be a differentiable function such that ∫0x g(t) dt = x - ∫0x t g(t) dt, x ≥ 0. Let y = y(x) satisfy the differential equation dy/dx - y tan x = 2(x + 1) sec x g(x), x ∈ [0, π/2). If y(0) = 0, then y(π/3) is equal to:

Q123 Apr 2025, Shift 2

Let y = y(x) be the solution of the differential equation dy/dx + 3(tan2 x) y + 3y = sec2 x, y(0) = 1/3 + e3. Then y(π/4) is equal to:

Q134 Apr 2025, Shift 1

Let f: [0, ∞) → R be a differentiable function such that f(x) = 1 - 2x + ∫0x e(x-t) f(t) dt for all x ∈ [0, ∞). Then, the area of the region bounded by y = f(x) and the coordinate axes is:

Q144 Apr 2025, Shift 2

If a curve y = y(x) passes through the point (1, π/2) and satisfies the differential equation (7x4 cot y - ex cosec y) dx/dy = x5, x ≥ 1, then at x = 2, the value of cos y is:

Q157 Apr 2025, Shift 1

Let y = y(x) be the solution curve of the differential equation x(x2 + ex) dy + (ex (x - 2) y - x3) dx = 0, x > 0, passing through the point (1, 0). Then y(2) is equal to:

Q167 Apr 2025, Shift 2

Let y = y(x) be the solution of the differential equation (x2 + 1) y2 - 2xy = (x4 + 2x2 + 1) cos x. y(0) = 1. Then ∫(-2)3 y(x) dx is:

Q178 Apr 2025, Shift 2

Let f(x) = x - 1 and g(x) = ex for x ∈ R. If dy/dx = (e(-2√x) g(f(f(x))) - y/√x), y(0) = 0, then y(1) is:

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2026 Questions (12)

Q121 Jan 2026, Shift 1

Let y = y(x) be the solution curve of the differential equation (1 + x2) dy + (y - tan-1 x) dx = 0, y(0) = 1. Then the value of y(1) is :

Q221 Jan 2026, Shift 2

Let y = y(x) be the solution of the differential equation sec x dy/dx - 2y = 2 + 3 sin x, x ∈ (-π/2, π/2), y(0) = -7/4. Then y(π/6) is equal to

Q322 Jan 2026, Shift 1

Let the solution curve of the differential equation x dy - y dx = sqrt(x2 + y2) dx, x > 0, y(1) = 0 be y = y(x). Then y(3) is equal to

Q422 Jan 2026, Shift 2

If y = y(x) satisfies the differential equation 16√x·√9+√x·(4+√9+√x) cos y dy = (1 + 2 sin y) dx, x > 0 and y(256) = π/2. If y(49) = α, then 2 sin α is equal to

Q523 Jan 2026, Shift 1

Let y = y(x) be the solution of the differential equation x4 dy + (4x3y + 2 sin x) dx = 0, x > 0, y(π/2) = 0. Then π4 y(π/3) is equal to

Q623 Jan 2026, Shift 2

If the solution curve y = f(x) of the differential equation (x2 - 4) y' = 2x(y2 - x(4 - x2)) - 20 passes through the point (3, 1.5), then the local maximum value of f is ____

Q728 Jan 2026, Shift 1

Let y = y(x) be the solution of the differential equation x dy/dx - sin 2y = x3(2 - x3) cos2 y, x ≠ 0. If y(2) = π, then tan(y(1)) is equal to

Q82 Apr 2026, Shift 1

Let y = y(x) be the solution curve of the differential equation (1 + sin x) dy/dx + (y + 1) cos x = 0, y(0) = 0. If the curve y = y(x) passes through the point (α, -1/2), then a value of α is :

Q92 Apr 2026, Shift 2

Let x = x(y) be the solution of the differential equation 2y2 dx/dy - 2xy + x2 = 0, y > 1, x(e) = e. Then x(e2) is equal to

Q104 Apr 2026, Shift 1

Let y = y(x) be the solution of the differential equation dy/dx = (1 + x + x2)(1 - y + y2), y(0) = 1/2. Then (2y(1) - 1) is equal to

Q116 Apr 2026, Shift 2

Let f : R → R be such that f(xy) = f(x)f(y), for all x, y ∈ R and f(0) ≠ 0. Let g : [1, ∞) → R be a differentiable function such that x2 g(x) = ∫1ˣ (t2 f(t) - t g(t)) dt. Then g(2) is equal to :

Q128 Apr 2026, Shift 2

Let y = y(x) be the solution of the differential equation x√1 - x2 dy + (y√1 - x2 - x cos-1 x) dx = 0, x ∈ (0, 1), lim(x→1-) y(x) = 1. Then y(1/2) equals :

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Frequently Asked Questions

How does the answer checking work in this quiz?
Pick an option for a multiple choice question, or type your answer for a numerical question and press Check. A correct choice turns green, a wrong choice turns red and the correct option turns green, and the short method appears below. Once answered, a card locks until you press Reset.
How many Differential Equations questions are in this quiz, and from which years?
63 verified JEE Main Differential Equations questions: 34 from 2024, 17 from 2025 and 12 from 2026, each in shift order.
How should I use this quiz for revision?
Attempt one year timed, without looking at the method. After checking, note every miss by pattern, such as linear equations, homogeneous equations, or Bernoulli equations, and rework that pattern the same day.
Why do some questions ask for a value instead of options?
Those are numerical questions from the paper itself, where the answer is a number, not a choice. Type the number and press Check; the check ignores units, spaces and case, with a small tolerance.
Are these real JEE Main questions?
Yes. Every question here is a verified JEE Main Differential Equations question from 2024, 2025 or 2026, shown with its shift.

Tags

JEE Main 2027Differential Equations PYQJEE Main MathsPYQ AnalysisRepeat FrequencyUPO Unique PYQsLinear Differential EquationsHomogeneous EquationsBernoulli EquationJEE Main Preparation

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