JEE Main Differential Equations PYQs 2024, 2025 and 2026: All Questions with Solutions
JEE Main Differential Equations PYQs 2024, 2025 and 2026: All Questions with Solutions
Verified JEE Main Differential Equations questions from 2024, 2025 and 2026, shift by shift. The 2024, 2025 and 2026 sets are interactive now: pick an option or enter a number and check instantly. Attempt timed, check the method only after answering, and log every miss by pattern.
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3. Read the short method only after answering, then log the miss by pattern.
4. Rework your weak patterns the same day, then reattempt the year.
2024 Questions (34)
If the solution of the differential equation (2x + 3y − 2) dx + (4x + 6y − 7) dy = 0, y(0) = 3, is αx + βy + 3 loge|2x + 3y − γ| = 6, then α + 2β + 3γ is equal to
Let x = x(t) and y = y(t) be solutions of the differential equations dx/dt + ax = 0 and dy/dt + by = 0 respectively, a, b ∈ R. Given that x(0) = 2, y(0) = 1 and 3y(1) = 2x(1), the value of t, for which x(t) = y(t), is
If the solution curve, of the differential equation dy/dx = (x + y − 2)/(x − y) passing through the point (2, 1) is tan−1((y−1)/(x−1)) − (1/β) loge(α + ((y−1)/(x−1))2) = loge|x−1|, then 5β + α is equal to
If y = y(x) is the solution curve of the differential equation (x2 − 4) dy − (y2 − 3y) dx = 0, x > 2, y(4) = 3/2 and the slope of the curve is never zero, then the value of y(10) equals
If the solution curve y = y(x) of the differential equation (1 + y2)(1 + loge x) dx + x dy = 0, x > 0 passes through the point (1, 1) and y(e) = (α − tan(3/2))/(β + tan(3/2)), then α + 2β is
A function y = f(x) satisfies f(x) sin 2x + sin x − (1 + cos2 x) f'(x) = 0 with condition f(0) = 0. Then, f(π/2) is equal to
Let f(x) = √limr→x { 2r2[(f(r))2 − f(x)f(r)]/(r2 − x2) − r3 ef(r)/r } be differentiable in (−∞, 0) ∪ (0, ∞) and f(1) = 1. Then the value of ea, such that f(a) = 0, is equal to
If sin(y/x) = loge|x| + α/2 is the solution of the differential equation x cos(y/x) dy/dx = y cos(y/x) + x and y(1) = π/3, then α2 is equal to
Let y = y(x) be the solution of the differential equation (1 − x2) dy = [xy + (x3 + 2)√3(1 − x2)] dx, −1 < x < 1, y(0) = 0. If y(1/2) = m/n, m and n are coprime numbers, then m + n is equal to
Let y = y(x) be the solution of the differential equation sec x dy − (2 sin x tan x + y) dx = 0 such that y(0) = 2. Then y(2) is equal to
Let Y = Y(X) be a curve lying in the first quadrant such that the area enclosed by the line Y - y = Y'(x)(X - x) and the co-ordinate axes, where (x, y) is any point on the curve, is always -y2 / (2Y'(x)) + 1, Y'(x) ≠ 0. If Y(1) = 1, then 12Y(2) is equal to
The solution curve of the differential equation y dx/dy = x(loge x − loge y + 1), x > 0, y > 0 passing through the point (e, 1) is
Let y = y(x) be the solution of the differential equation dy/dx = ((tan x) + y)/(sin x (sec x − sin x tan x)), x ∈ (0, π/2) satisfying the condition y(π/4) = 2. Then, y(π/3) is
The temperature T(t) of a body at time t = 0 is 160°F and it decreases continuously as per the differential equation dT/dt = −k(T − 80), where k is positive constant. If T(15) = 120°F, then T(45) is equal to
Let y = y(x) be the solution of the differential equation sec2 x dx + (e2y tan2 x + tan x) dy = 0, 0 < x < π/2, y(π/4) = 0. If y(π/6) = α, then e8α is equal to ___
If x = x(t) is the solution of the differential equation (t + 1) dx = (2x + (t + 1)4) dt, x(0) = 2, then x(1) equals
Let y = y(x) be the solution of the differential equation dy/dx = 2x(x + y3)/(xy − 1), y(0) = 1. Then (1/√2 + y(1/√2))2 equals
Let the solution y = y(x) of the differential equation dy/dx − y = 1 + 4 sin x satisfy y(π) = 1. Then y(π/2) + 10 is equal to
If the solution y = y(x) of the differential equation (x4 + 2x3 + 3x2 + 2x + 2) dy − (2x2 + 2x + 3) dx = 0 satisfies y(−1) = −π/4, then y(0) is equal to
Let y = y(x) solve (x + y + 2)2 dx = dy, y(0) = −2. Let α, β be the maximum and minimum of y(x) on [0, π/3]. If (3α + π)2 + β2 = γ + δ√3, γ, δ integers, then γ + δ equals
Let y = y(x) be the solution of the differential equation (x2 + 4)2 dy + (2x3 y + 8xy − 2) dx = 0. If y(0) = 0, then y(2) is equal to
Let f be a differentiable function in the interval (0, ∞) such that f(1) = 1 and limt→x (t2 f(x) − x2 f(t))/(t − x) = 1 for each x > 0. Then 2f(2) + 3f(3) is equal to
If y = y(x) is the solution of the differential equation dy/dx + 2y = sin 2x, y(0) = 3/4, then y(π/8) is equal to
Let y = y(x) be the solution of the differential equation dy/dx = 2x/(1 + x2)2 − y e1/(1 + x2), y(0) = 0. Then the area enclosed by the curve f(x) = y(x) e1/(1 + x2) and the line y − x = 4 is ____.
The differential equation of the family of circles passing the origin and having center at the line y = x is
A conic C passes through (4, −2). At any point P(x, y), x ≥ 3, on C, the tangent slope is half the slope of the line joining P to (3, −5). If the focal distance of (7, 1) on C is d, then 12d equals ____.
Let y = y(x) be the solution of the differential equation (2 + x loge x) dy/dx + 2y = 3x loge x, x > 0 and y(e−1) = 0. Then, y(e) is equal to ____.
Let y = y(x) be the solution of the differential equation (1 + x2) dy/dx + y = etan−1 x, y(1) = 0. Then y(0) is ____.
Let y = y(x) be the solution of the differential equation (1 + y2) etan x dx − cos2 x (1 + e2 tan x) dy = 0, y(0) = 1. Then y(π/4) is equal to
Let f(x) be positive such that the area bounded by y = f(x), y = 0, from x = 0 to x = a > 0 is e−a + 4a2 + a − 1. The differential equation whose general solution is y = c1f(x) + c2 is
The solution of the differential equation (x2 + y2) dx − 5xy dy = 0, y(1) = 0 is
The solution curve of the differential equation 2y dy/dx + 3 = 5 dy/dx passing through the point (0, 1) is a conic whose vertex lies on the line
For a differentiable function f: R → R, suppose f'(x) = 3 f(x) + α, where α ∈ R, f(0) = 1 and limx→−∞ f(x) = 7. Then 9 f(−loge 3) is equal to
Let ∫0x √1 − (y'(t))2 dt = ∫0x y(t) dt, 0 ≤ x ≤ 3, y ≥ 0, y(0) = 0. Then at x = 2, y'' + y + 1 is equal to :
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2025 Questions (17)
If x = f(y) is the solution of the differential equation (1 + y2) + (x - 2e(tan-1 y)) dy/dx = 0, y ∈ (-π/2, π/2) with f(0) = 1, then f(1/√3) is equal to:
Let a curve y = f(x) pass through the points (0, 5) and (loge 2, k). If the curve satisfies the differential equation 2(3 + y) e(2x) dx - (7 + e(2x)) dy = 0, then k is equal to:
Let x = x(y) be the solution of the differential equation y = (x - y dx/dy) sin(x/y), y > 0 and x(1) = π/2. Then cos(x(2)) is equal to:
Let y = y(x) be the solution of the differential equation (xy - 5x2 √1 + x2) dx + (1 + x2) dy = 0, y(0) = 0. Then y(√3) is equal to:
Let y = y(x) be the solution of the differential equation 2 cos x dy/dx + sin 2x - 4y sin x = 0, x ∈ (0, π/2). If y(π/3) = 0, then y'(π/4) + y(π/4) is equal to:
If y = y(x) is the solution of the differential equation √4 - x2 dy/dx = ((sin-1(x/2))2 - y) sin-1(x/2), -2 ≤ x ≤ 2, y(2) = (π2 - 8)/4, then y2(0) is equal to:
Let y = y(x) be the solution of the differential equation cos x (loge (cos x))2 dy + (sin x - 3y sin x loge (cos x)) dx = 0, x ∈ (0, π/2). If y(π/4) = -1/loge 2, then y(π/6) is equal to:
If for the solution curve y = f(x) of the differential equation dy/dx + (tan x) y = (2 + sec x)/(1 + 2 sec x)2, x ∈ (-π/2, π/2), f(π/3) = √3/10, then f(π/4) is equal to:
Let f: R → R be a thrice differentiable odd function satisfying f'(x) ≥ 0, f''(x) = f(x), f(0) = 0, f'(0) = 3. Then 9f(loge 3) is equal to ______.
Let y = y(x) be the solution of the differential equation dy/dx + 2y sec2 x = 2 sec2 x + 3 tan x · sec2 x such that y(0) = 5/4. Then 12(y(π/4) - e(-2)) is equal to ____.
Let g be a differentiable function such that ∫0x g(t) dt = x - ∫0x t g(t) dt, x ≥ 0. Let y = y(x) satisfy the differential equation dy/dx - y tan x = 2(x + 1) sec x g(x), x ∈ [0, π/2). If y(0) = 0, then y(π/3) is equal to:
Let y = y(x) be the solution of the differential equation dy/dx + 3(tan2 x) y + 3y = sec2 x, y(0) = 1/3 + e3. Then y(π/4) is equal to:
Let f: [0, ∞) → R be a differentiable function such that f(x) = 1 - 2x + ∫0x e(x-t) f(t) dt for all x ∈ [0, ∞). Then, the area of the region bounded by y = f(x) and the coordinate axes is:
If a curve y = y(x) passes through the point (1, π/2) and satisfies the differential equation (7x4 cot y - ex cosec y) dx/dy = x5, x ≥ 1, then at x = 2, the value of cos y is:
Let y = y(x) be the solution curve of the differential equation x(x2 + ex) dy + (ex (x - 2) y - x3) dx = 0, x > 0, passing through the point (1, 0). Then y(2) is equal to:
Let y = y(x) be the solution of the differential equation (x2 + 1) y2 - 2xy = (x4 + 2x2 + 1) cos x. y(0) = 1. Then ∫(-2)3 y(x) dx is:
Let f(x) = x - 1 and g(x) = ex for x ∈ R. If dy/dx = (e(-2√x) g(f(f(x))) - y/√x), y(0) = 0, then y(1) is:
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2026 Questions (12)
Let y = y(x) be the solution curve of the differential equation (1 + x2) dy + (y - tan-1 x) dx = 0, y(0) = 1. Then the value of y(1) is :
Let y = y(x) be the solution of the differential equation sec x dy/dx - 2y = 2 + 3 sin x, x ∈ (-π/2, π/2), y(0) = -7/4. Then y(π/6) is equal to
Let the solution curve of the differential equation x dy - y dx = sqrt(x2 + y2) dx, x > 0, y(1) = 0 be y = y(x). Then y(3) is equal to
If y = y(x) satisfies the differential equation 16√x·√9+√x·(4+√9+√x) cos y dy = (1 + 2 sin y) dx, x > 0 and y(256) = π/2. If y(49) = α, then 2 sin α is equal to
Let y = y(x) be the solution of the differential equation x4 dy + (4x3y + 2 sin x) dx = 0, x > 0, y(π/2) = 0. Then π4 y(π/3) is equal to
If the solution curve y = f(x) of the differential equation (x2 - 4) y' = 2x(y2 - x(4 - x2)) - 20 passes through the point (3, 1.5), then the local maximum value of f is ____
Let y = y(x) be the solution of the differential equation x dy/dx - sin 2y = x3(2 - x3) cos2 y, x ≠ 0. If y(2) = π, then tan(y(1)) is equal to
Let y = y(x) be the solution curve of the differential equation (1 + sin x) dy/dx + (y + 1) cos x = 0, y(0) = 0. If the curve y = y(x) passes through the point (α, -1/2), then a value of α is :
Let x = x(y) be the solution of the differential equation 2y2 dx/dy - 2xy + x2 = 0, y > 1, x(e) = e. Then x(e2) is equal to
Let y = y(x) be the solution of the differential equation dy/dx = (1 + x + x2)(1 - y + y2), y(0) = 1/2. Then (2y(1) - 1) is equal to
Let f : R → R be such that f(xy) = f(x)f(y), for all x, y ∈ R and f(0) ≠ 0. Let g : [1, ∞) → R be a differentiable function such that x2 g(x) = ∫1ˣ (t2 f(t) - t g(t)) dt. Then g(2) is equal to :
Let y = y(x) be the solution of the differential equation x√1 - x2 dy + (y√1 - x2 - x cos-1 x) dx = 0, x ∈ (0, 1), lim(x→1-) y(x) = 1. Then y(1/2) equals :
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