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JEE MAIN 20241
310124 S2
Question
If two vectors $\overrightarrow{\mathrm{A}}$ and $\overrightarrow{\mathrm{B}}$ having equal magnitude $R$ are inclined at an angle $\theta$, then
Select the correct option:
A
$|\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}|=\sqrt{2} \mathrm{R} \sin \left(\frac{\theta}{2}\right)$
B
$|\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}|=2 \mathrm{R} \sin \left(\frac{\theta}{2}\right)$
C
$|\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}|=2 \mathrm{R} \cos \left(\frac{\theta}{2}\right)$
D
$|\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}}|=2 \mathrm{R} \cos \left(\frac{\theta}{2}\right)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
The magnitude of resultant vector $R^{\prime}=\sqrt{a^2+b^2+2 a b \cos \theta}$ Here $\mathrm{a}=\mathrm{b}=\mathrm{R}$ Then $R^{\prime}=\sqrt{R^2+R^2+2 R^2 \cos \theta}$ $$ \begin{aligned} & =R \sqrt{2} \sqrt{1+\cos \theta} \\ & =\sqrt{2} R \sqrt{2 \cos ^2 \frac{\theta}{2}} \\ & =2 R \cos \frac{\theta}{2} \end{aligned} $$
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