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JEE MAIN 2021
20-07-2021 S2
Question
Lef $f: R-\left\{\frac{\alpha}{6}\right\} \rightarrow R$ be defined by $f(x)=\frac{5 x+3}{6 x-\alpha}$. Then the value of $\alpha$ for which (fof) $(x)=x$, for all $x \in R-\left\{\frac{\alpha}{6}\right\}$, is
Select the correct option:
A
No such $\alpha$ exists
B
5
C
8
D
6
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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