Let $f:\left(-\frac{\pi}{4}, \frac{\pi}{4}\right) \rightarrow R$ be defined as $f(x)=\left\{\begin{array}{cc}(1+|\sin x|)^{\frac{3 a}{|\sin x|}}, & -\frac{\pi}{4}
If $f$ is continuous at $x=0$, then the value of $6 a+b^2$ is equal to:
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