The value of cot(∑ from n=1 to 19 cot⁻¹(1+∑2p))... | Trigonometric Series | JEE Main

JEE MAIN 2019

10-01-2019 S2

Question

The value of $\cot \left(\sum_{n=1}^{19} \cot ^{-1}\left(1+\sum_{p=1}^n 2 p\right)\right)$ is

Select the correct option:

A

$\frac{19}{21}$

B

$\frac{23}{22}$

C

$\frac{22}{23}$

D

$\frac{21}{19}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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