If $\left|\begin{array}{ccc}a-b-c & 2 a & 2 a \\ 2 b & b-c-a & 2 b \\ 2 c & 2 c & c-a-b\end{array}\right|=(a+b+c)(x+a+b+c)^2, x \neq 0$ and $a+b+c \neq 0$, then $x$ is equal to:
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