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JEE MAIN 2020
06.09.20_S1
Question
An electron is moving along $+x$ direction with a velocity of $6 \times 10^6 \mathrm{~ms}^{-1}$. It enters a region of uniform electric field of $300 \mathrm{~V} / \mathrm{cm}$ pointing along $+y$ direction. The magnitude and direction of the magnetic field set up in this region such that the electron keeps moving along the $x$ direction will be
Select the correct option:
A
$5 \times 10^{-3} \mathrm{~T}$, along +z direction
B
$5 \times 10^{-3} \mathrm{~T}$, along -z direction
C
$3 \times 10^{-4} \mathrm{~T}$, along +z direction
D
$3 \times 10^{-4} \mathrm{~T}$, along -z direction
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & F=q(\vec{E}+\vec{V} \times \vec{B}) \\ & \vec{E}+\vec{V} \times \vec{B}=0\end{aligned}$
Question Tags
JEE Main
Physics
Easy
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