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JEE MAIN 2020
6-9-20_(S1)
Question
A solution of two components containing $n_1$ moles of the $1^{\text {st }}$ component and $n_2$ moles of the $2^{\text {nd }}$ component is prepared. $M_1$ and $M_2$ are the molecular weights of component 1 and 2 respectively. If d is the density of the solution in $\mathrm{g} \mathrm{mL}^{-1}, \mathrm{C}_2$ is the molarity and $\mathrm{x}_2$ is the mole fraction of the $2^{\text {nd }}$ component, then $\mathrm{C}_2$ can be expressed as
Select the correct option:
A
$C_2=\frac{1000 x_2}{M_1+x_2\left(M_2-M_1\right)}$
B
$\mathrm{C}_2=\frac{1000 \mathrm{dx}_2}{\mathrm{M}_1+\mathrm{x}_2\left(\mathrm{M}_2-\mathrm{M}_1\right)}$
C
$C_2=\frac{d x_2}{M_2+x_2\left(M_2-M_1\right)}$
D
$C_2=\frac{d x_1}{M_2+x_2\left(M_2-M_1\right)}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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