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JEE MAIN 2026
21-01-2026 S2
Question
If P is a point on the circle $x^2+y^2=4, \mathrm{Q}$ is a point on the straight line $5 x+y+2=0$ and $x-y+1=0$ is the perpendicular bisector of PQ , then 13 times the sum of abscissa of all such points P is $\_\_\_\_$ .
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Question Tags
JEE Main
Mathematics
Hard
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